Question

Plzz help to solve this

Answer 1

I hope it is not wrong and helps you frnd

Answer 2

Here let us take 2 triangles I.e. triangle DCF bad triangle BFE
Now in the 2 triangles

CF = BF (F is the mid point)
angle DCB=angle CBE (DC is parallel to AB so DC parallel to BE , alternate angles)
also, angle CDE =angle BED ( same reason )

So triangle DCF is congruent to triangle BFE

DF=FE (CPCT)
Thus F is the mid point of DE .