plzz help with ques no. 15
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Solution:-
[ ( 1 + cot²θ)tanθ / sec²θ ] = cotθ
L.H.S.
=) [ ( 1 + cot²θ)tanθ / sec²θ ]
=) [ cosec²θ . tanθ / sec²θ ]
=) [ (1/sin²θ) ( sinθ/cosθ ) / sec²θ ]
=) [ (1/ sinθ. cosθ)/( 1/cos²θ ) ]
=) [ ( 1/ sinθ ) / ( 1/cosθ ) ]
=) [ cosθ / sinθ ]
=) cotθ
L.H.S = R.H.S.
Hence Proved!
Identity Used :-
- ( 1 + cot²θ ) = cosec²θ
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