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the zeroes of the quadratic polynomial is alpha and beta form a quadratic polynomial whose zeroes are 3alpha and 3bete
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Step-by-step explanation:
zeroes are
alpha = 3 and beta = 3
sum of zeroes = 3 +3 =6
product of zeroes = 3×3 = 9
let quadratic equation be ax^2 + bx + c
let a = 1,
sum of zeroes = - (b) / a
6 = - b/ 1
- 6 = b
product of zeroes = c / a
9 = c / 1
9 = c
putting the values of a, b and c in the quadratic equation we get,
x^2 - 6x + 9
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