Question

plzz hep vey urgent prove that​

Answer 1

Step-by-step explanation:

(sin 9A+ sin A)+sin5A

-------------------

(cos9A+ cosA)+cos5A

2.sin 5A.cos.4A+ sin 5A

--------------------

2.cos 5A.cos4A+ cos5A

by taking sin5A common we get

sin5A

------

cos 5A

=tan 5A

Answer 2

Answer:

three formula are used to solve this,

$\sin( \alpha ) + \sin( \beta ) = 2 \sin( \frac{ \alpha + \beta }{2} ) \cos( \frac{ \alpha - \beta }{2} ) \\ \cos( \alpha ) + \cos( \beta ) = 2 \cos( \frac{ \alpha + \beta }{2} ) \cos( \frac{ \alpha - \beta }{2} ) \\ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \tan( \alpha )$