Question

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Answer 1

Answer:

Answer:Principal = ₹10000

Answer:Principal = ₹10000Amount = ₹11200

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000)

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years Let the rate of interest be R

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years Let the rate of interest be R Therefore, S.I. = P×R×T /100

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years Let the rate of interest be R Therefore, S.I. = P×R×T /100 1200= 10000×R× 2/100

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years Let the rate of interest be R Therefore, S.I. = P×R×T /100 1200= 10000×R× 2/100 1200×100= 10000×R×2

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years Let the rate of interest be R Therefore, S.I. = P×R×T /100 1200= 10000×R× 2/100 1200×100= 10000×R×2 R = 1200× 100/10000×2

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years Let the rate of interest be R Therefore, S.I. = P×R×T /100 1200= 10000×R× 2/100 1200×100= 10000×R×2 R = 1200× 100/10000×2 R = 6% p.a.

Answer:Principal = ₹10000Amount = ₹11200Simple Interest = ₹(11200 - 10000) = ₹ 1200Time = 2 years Let the rate of interest be R Therefore, S.I. = P×R×T /100 1200= 10000×R× 2/100 1200×100= 10000×R×2 R = 1200× 100/10000×2 R = 6% p.a.Therefore , rate of interest is 6%p.a.

The principal at the beginning of the second year = ₹11200

Time =1 year

Rate =6%p.a.

Therefore , S.I. = ₹11200× 6×1/100

= ₹112×6

=₹672

Therefore , amount = ₹ 11200+₹ 672

₹ 11872

Therefore , the amount at the end of second year is ₹ 11872