Question

plzz itss urgent factorise √2x²-3/√2x+1/√2​

Answer 1

Required Answer:-

Given:

• $\sf \sqrt{2} {x}^{2} - \dfrac{3}{ \sqrt{2} } x + \dfrac{1}{ \sqrt{2} } = 0$

To find:

• The values of x satisfying the equation.

Solution:

We have,

$\sf \implies \sqrt{2} {x}^{2} - \dfrac{3}{ \sqrt{2} } x + \dfrac{1}{ \sqrt{2} } = 0$

Multiplying both sides by √2, we get,

$\sf \implies 2{x}^{2} - 3 x + 1= 0$

This is in general form. Factorise it.

$\sf \implies 2{x}^{2} - 2 x - x+ 1= 0$

$\sf \implies 2x(x -1) - 1(x - 1) = 0$

$\sf \implies (2x - 1)(x - 1) = 0$

By zero product rule,

➡ Either (2x - 1) = 0 or (x - 1) = 0

Therefore,

➡ x = 1/2, 1

Hence, the possible values of x are 1/2 and 1.

Answer:

• The values of x satisfying the given equation are ½ and 1.