Math, asked by namanpreetkaur710, 8 months ago

plzz make equation and solve it with quadratic formula ​

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Answered by NAGUVEDU2016
1

ANSWER

Two taps be A and B , A Larger Tap , B Smaller Tap

Together that will be filled the tank in A+B = 75/8 hrs...

In one hour tank will fill = 1/A + 1/B = 1 / (75/8) hrs...

Consider Smaller tap takes X hrs to fill tank

In one hrs it fill the tank , 1/B = 1 / X hrs

A takes individual to fill tank = X - 10 hrs

In one hrs it will fill the tank , 1/A = 1 / (X - 10)hrs

Then

1/A+1/B= 1/(75/8)

1/(X-10)+1/X= 8/75

X+X-10 / X(X-10) = 8/75

2X-10 / X^2 - 10X = 8/75

75×2X -75×10 = 8X^2 - 8× 10X

150X - 750 = 8X^2 - 80X

8X^2 - 230X + 750 = 0

Divided whole thing by 2

4X^2 - 115X + 375 = 0

4X^2 - 100X - 15X + (-25 × -15) = 0

4X (X - 25) - 15 ( X - 25) = 0

(4X - 15) ( X - 25) = 0

X - 25 = 0 , 4X - 15 = 0

X = 25 , X = 15 / 4

Smaller tap takes = 25 hrs

Larger tap takes = 25 - 10 hrs = 15 hrs..

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