Question

plzz mate ans this one correctly​

Answer 1

Answer:

60°

Step-by-step explanation:

In ∆ABC and ∆A'B'C'

AB = A'B' (given = 6cm)

angle ABC = angle A'B'C' (given = 60°)

BC = B'C' (given = 6cm)

∆ABC and ∆A'B'C' (S.A.S.)

angle BAC = angle B'A'C' (C.P.C.T.)

3x = 2x + 20

3x - 2x = 20

x = 20°

angle B'A'C' = 2x + 20

= 2*20 + 20

= 40 + 20

= 60°

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