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Answers
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Answer:
1.)19 moles
2.)1.1441×10²⁵ molecules
3.)1.1441×10²⁵ atoms of Sulphur and 2.2882×10²⁵ atoms of oxygen
4.)425.6L
5.)18.066×10²³atoms
Explanation:
ANSWER 1.):-
No. of moles=given mass/molecular mass
No. of moles of S0₂=1216/64=19 moles
ANSWER 2.):-
No. of molecules=Given mass/molecular mass ×Avogadro number
No. of molecules of SO₂=1216/64×6.022×10²³
=19×6.022×10²³=114.41×10²³
=1.1441×10²⁵ molecules
ANSWER 3.):-
No. of sulphur atoms present in 1216 g SO₂
=No. of atoms of sulphur×Given mass/Molecular mass×Avogadro number
=1×1216/64×6.022×10²³==114.41×10²³
=1.1441×10²⁵ atoms of Sulphur
No. of oxygen atoms present in 1216 g SO₂
=No. of atoms of oxygen×Given mass/Molecular mass×Avogadro number
=2×1216/64×6.022×10²³=114.41×10²³×2=1.1441×10²⁵×2=2.2882×10²⁵ atoms
ANSWER 4.):-
Volume of SO₂=Given mass/Molecular mass×22.4L
=1216/64×22.4L=19×22.4L=425.6L
ANSWER 5.):-
No. of oxygen atoms present in 48g of O₃
=No. of atoms of oxygen×Given mass/Molecular mass×Avogadro number
=3×48/48×6.022×10²³=3×1×6.022×10²³=18.066×10²³atoms
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Answer:
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