Physics, asked by aadityapatro2009, 10 months ago

plzz plzz koi mere inn dono que ko solve kardo​

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Answered by ankurgoswami1976
2

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(ans-1) E=hf=hcλ(energy of a photon) E = h f = h c λ (energy of a photon) , ... When working with small systems, energy in eV is often useful. Note that Planck's constant in these units is h = 4.14 × 10−15 eV · s. Since many wavelengths are stated in nanometers (nm), it is also useful to know that hc = 1240 eV · nm.

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sorry I just don't know the second one

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