plzz plzz plzz help me guys just for some days then i will leave....how many natural numbers are there between 100 and 1000, which have at least one of their digits as 5?( by permutation method) i need it please
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total waus of filling digits =9×10×10
total no. of ways in which ,at least one no.is 5=total ways - total ways in which no digit is five
total ways in which no digit is 5=8×9×9
required ways=900-648
=252
hope it helps you dude.......
Answered by
1
Answer:
Step-by-step explanation:
total ways of filling digits =9×10×10
total no. of ways in which ,at least one no.is 5=total ways - total ways in which no digit is five
total ways in which no digit is 5=8×9×9
required ways=900-648
=252
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