Question

plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz plzz ans it is very urgent

Answer 1

hey .......................this....is......an.....s......

Answer 2

Answer:

1

Step-by-step explanation:

Important Formulas:

(i) tanθ = (1/cotθ)

(ii) sin(90 - θ) = cosθ

(iii) cos(90 - θ) = sinθ

(iv) tan(90 - θ) = cotθ

(v) cosec(90 - θ) = secθ

(vi) cot(90 - θ) = tanθ

Now,

$Given:\frac{7cos55}{3sin35}- \frac{4(cos70cosec20)}{3(tan5tan25tan45tan65tan85}$

$=\frac{7cos55}{3cos(90-35)}-\frac{4cos70*sec(90-20)}{3 tan5*tan85 * tan25*tan65*tan45}$

$=\frac{7 cos55}{3cos55}-\frac{4cos70*sec70}{3tan5*cot(90 - 85)*tan25 *cot(90 - 65)*tan45 }$

$=\frac{7}{3}-\frac{4 cos70*\frac{1}{cos70}}{tan5*\frac{1}{tan5}*tan25*\frac{1}{tan25}*1}$

$=\frac{7}{3}-\frac{4}{3}$

$=\frac{7-4}{3}$

$=\frac{3}{3}$

$=\boxed{1}$

Hope it helps!