plzz plzz solve this question
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Hello friend According to question angle of projection with horizontal is 30degree. Now we split it ti horizontal and vertical component since velocity is 14 then vetical = 14sin30=7 Horizontal velocity =14cos30=7root3 To find horizontal range we need time period Now, height of building(assume ) is 12 Since s=ut+1/2at^2 12=7t+5t^2 T=1 other is left bcz time never negative Therefore horizontal range =hor. Vel. *t=7squareroot3 Hope it helps u
girishmehta72:
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