Question

plzz see this attachment plzzz slove​

Answer 1

Answer:

Given a, b, c are roots of equation x³+3x²-x-3=0

From equation

a+b+c=-b/a =-3

ab+bc+ca=c/a=-1

abc=-d/a=3

1/a+1/b+1/c = (ab+bc+ca) /abc

= - 1/3

Instead of alpha, beta, gama I took a, b, c

Answer 2

in a cubic polynomial ax^3+bx^2+cx+d=0

the sum of roots =-b/a

the product of roots is -d/a

the sum of product of roots is c/a

so

now see the attachment

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