Question

Plzz simplify this as fast as you can

Answer 1

Answer:

$({ \sqrt[4]{81}}^{3} \times { \sqrt[3]{27}}^{ - 2} ) \div {\sqrt{18}}^{3}$

=

$(27 \times {9}^{ - 1} ) \div \sqrt{5832}$

=

$3 \div \sqrt{5832}$

=

$\sqrt{9} \div \sqrt{5832}$

=

$1 \div \sqrt{648}$

=

${ \sqrt{648} }^{ - 1}$