Question

plzz slove this:

2y^2 = 17 * y - 8

Answer 1

Given Equation is 2y^2 = 17y - 8

2y^2 + 8 = 17y

2y^2 - 17y + 8 = 0

2y^2 - 16y - y + 8 = 0

2y(y - 8) - 1(y - 8) = 0

(2y - 1)(y - 8) = 0

y = 1/2,8.


Hope this helps!

Answer 2

I hope it will helps u...