plzz sole this que 14 and 15
Answers
hyy
= Let a,b,c be the sides of the triangle [trngl]
= Perimeter 2s = a + b + c
= Semi-perimeter, s = (a+b+c)/2
= Using Heron's formula:
= Area of the trngl A = √s(s−a)(s−b)(s−c)
= Now, if the sides are doubled: 2a, 2b, 2c
= Let s' be the smi-perimeter.
= 2s' = 2a + 2b + 2c
= s' = a + b + c
= or s' = 2s
= Area of the trngl, A' = √s′(s′−2a)(s′−2b)(s′−2c)
A' = √(2s)(2s−2a)(2s−2b)(2s−2c)
A' = √24s(s−a)(s−b)(s−c)
A' = 4√s(s−a)(s−b)(s−c)
A' = 4A
A':A = 4:1
∴ the ratio of area of the new tri and old tri is 4:1
now q.no 15
cylinder
r=7cm ,h=17 cm
cone
h=6 cm ,r=7cm
vol.of cylinder= pi r 2 h
= 22/7*7*7*17 = 2618cm3
vol.of cone 1/3 pi r2 h
=1/3*22/7*7*7*6
=308cm3
totl vol.of juice in glas = vol.of cylinder - vol of cone
=2168-308 =2310 cm3
=2.31 lt
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