plzz solv Q 14 ..... plzz solve it fast
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Given:-
ABCD is a parallelogram
AM and CN are perpendiculars on BD
To prove:-
AM=CN
Proof:-
first we have to prove ∆AMB=~ ∆CND
AB = CD(opp. sides of a parallelogram are equal)
angle AMB =angle CND(AM & CN are perpendiculars on BD)
angle ABM = angle CDN (alternate interior angle) (AB || CD,BD is transversal)
therefore,∆AMB =~ ∆CND (by A.A.S.)
AM=CN ( by C.P.C.T)
HENCE , PROVED!
ABCD is a parallelogram
AM and CN are perpendiculars on BD
To prove:-
AM=CN
Proof:-
first we have to prove ∆AMB=~ ∆CND
AB = CD(opp. sides of a parallelogram are equal)
angle AMB =angle CND(AM & CN are perpendiculars on BD)
angle ABM = angle CDN (alternate interior angle) (AB || CD,BD is transversal)
therefore,∆AMB =~ ∆CND (by A.A.S.)
AM=CN ( by C.P.C.T)
HENCE , PROVED!
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