Question

PLZZ SOLVE......

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Answer 1

Answer:

sin = 1/cosec

cos = 1/sec

tan = 1/cot

Hope it will help you.

Answer 2

हल:-

ΔPMN यह समकोण Δ है |

m<N = 90° , <P तथा <N परस्पर कोटीपुरक है|

.°. यदि m<N = 90° , m<p = 90 - ∅

आक्रति सें,

➠sin∅ = PM / PN ------(1)

➠ cos∅ = NM / PN ----(2)

➠ tan∅ = PM/NM -----(3)

आक्रति सें,

➠sin(90-∅ )= NM/PN-----(4)

➠cos(90-∅ )= PM / PN ----(5)

➠tan(90-∅ )= NM / PM ----(6)

➠ .°. sin∅ = cos(90-∅ ) -----(1) & (5) सें

➠ cos∅ = sin(90-∅) ------(2) & (4) सें

अब आप इसे भीं समझिऐ,

➠tan∅ × tan(90-∅ ) = PM/NM / NM / PM ---(3)& (6) सें

➠ .°. tan∅ ×tan(90-∅ ) = 1

इसी प्रकार,

sin∅ /cos∅ = PM / PN / NM / PN

= PM / PN × NM / PN

= PM / NM

= tan∅

हमने क्या समझा,

1)sin∅ = cos(90-∅ )

2)cos∅ = sin(90-∅)

3)tan∅ ×tan(90-∅ ) = 1

4)sin∅ /cos∅ = tan∅