plzz solve all the 3 ques
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These are ur answers hope it will help u
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1. Initial price is 1 per liter and increased price = 52.
Difference = 52 - 1 = 51 rupees.
Increase in price % = 51 * 100
= 5100.
2. Given SP = 250 and profit = 5%. .
We know that Cost price = (100 * SP) / (100 + Gain)
Cost price = (100 * 250) / 105
Cost price = (100 * 250) / 105
= 238.
3. Given P = 2400, R = 5 and S.I = 240.
We know that SI = PRT/100
240 = 2400 * 5 * T/100
T = 240 * 100/2400 * 5
= 2 years.
Hope this helps!
Difference = 52 - 1 = 51 rupees.
Increase in price % = 51 * 100
= 5100.
2. Given SP = 250 and profit = 5%. .
We know that Cost price = (100 * SP) / (100 + Gain)
Cost price = (100 * 250) / 105
Cost price = (100 * 250) / 105
= 238.
3. Given P = 2400, R = 5 and S.I = 240.
We know that SI = PRT/100
240 = 2400 * 5 * T/100
T = 240 * 100/2400 * 5
= 2 years.
Hope this helps!
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