Science, asked by KhanAku, 1 year ago

plzz solve all these three questions

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Answered by aks59
1

1). \: total \: watt  \: of \: bulb \:  \\    =  > 40 \times 5 = 200watt \\   total \: hr. \: of \:1month(30day) \\  =  > 30 \times 5 = 150 \: hr. \\ electrical \: energy \: used \: in \: one \: month. \\  =  > 200 \times 150 = 30000 \: watt \: ph \\  =  > \frac{30000}{1000}  = 30kwph \\ w.k.t. \\1 \: unit = 1kwph(1000wph) \\ now. \\ 30kwph = 30unit = 30rupees
I hope it will helps you

KhanAku: thnkkuu.... nd plzz try to solve all those remaining questions..plZ
aks59: ok I will try to do
KhanAku: kk
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