Math, asked by subesinghkalyan, 7 months ago

plzz solve as soon as possible. l will mark u as brainlist​

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Answers

Answered by amitsnh
0

Answer:

integration of 1/(sin^2xcos^2x) dx

= (sin^2x + cos^2x)/sin^2xcos^2x dx

= sin^2x/sin^2xcos^2x dx+ cos^2x/sin^2xcos^2x dx

= dx/cos^2x + dx/sin^2x

= sec^2x dx + cosec^2x dx

= tanx + (-cotx) + c

= tanx - cotx + c

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