Question

plzz solve it...... ​

Answer 1

${\mathfrak{\underline{\red{\:\:\: Given:-\:\:\:}}}}$

• $\:\:\:\:\bullet\:\:\:\sf{Mass \: of \: object(m) = 5 \: kg }$

• $\:\:\:\:\bullet\:\:\:\sf{Force(F) = 20 \: N}$

• $\:\:\:\:\bullet\:\:\:\sf{Displacement(s) = 25 \: cm}$

${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}}$

• $\:\:\:\:\bullet\:\:\:\sf{Work \: done \: by \: gravity \:( W.D_{g}) }$

• $\:\:\:\:\bullet\:\:\:\sf{Work \: done \: by \: force\:( W.D_{F})}$

${\mathfrak{\underline{\pink{\:\:\: Calculation:-\:\:\:}}}}$

☯ According to the given data:-

• $\\ \:\:\:\:\bullet\:\:\:\sf{s = \dfrac{25}{100} = 0.25\:m}$

• $\:\:\:\:\bullet\:\:\:\sf{cos \: \theta_{1} = 90 \degree}$

• $\:\:\:\:\bullet\:\:\:\sf{cos \: \theta_{2} = 0 \degree}$

☯ Finding the work done by gravity:—

• $\dashrightarrow\:\: \sf{ W.D_{g} = mg \: s \: cos \: \theta_{1}}$

• $\dashrightarrow\:\: \sf{W.D_{g} =5 \times 10 \times 0.25\times cos \: 90 \degree }$

• $\dashrightarrow\:\: \sf{ W.D_{g} =12.5 \times 0 }$

• $\dashrightarrow\:\: {\boxed{\sf{W.D_{g} =0 \: joule }}}$

☯ Finding the work done by force:—

• $\dashrightarrow\:\: \sf{ W.D_{F} = F\: s \: cos \: \theta_{2}}$

$\dashrightarrow\:\: \sf{W.D_{F} =20 \times 0.25 \times cos \: 0 \degree }$

$\dashrightarrow\:\:{\boxed{\sf{W.D_{F} = 5 \: joule }}}$

Answer 2

Given

• Mass of object(m) = 5 kg

• Force(F) = 20 N

Displacement(s) = 25 cm

To Find : -

• Work done by gravity (W.D:)

• Work done by force (W.DF)

Calculation :

According to the given data:

25 • S= = 0.25 m

100

• cos 01 90°

• cos 02 = 0°

Finding the work done by gravity:

--> W.Dg mg s cos 01W.

W.DF = Fs cos 02

W.DF 20 x 0.25 x cos 0°

-->

W.DF = 5 joule

Thnx ✌️✌️

W.Dg = 5 x 10 x 0.25 x cos 90°

W.Dg = 12.5 x 0

W.Dg = 0 joule =

Finding the work done by force:

W.DF = Fs cos 02