Plzz solve it by step by step explained
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ur answer is attached:
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lastbenchstudent:
there is a minor mistake there. you have calculated the value of x correct but calculated number of coins wrong in last.
2 rs coins are 3 times of 5 rs coins, so your 2 rs coins are 42 and 5 rs coins are 35 and 42 is not 3 times of 35. did u get it what am trying to say
ur correct ace5783....
how is that even possible ? if count of 2rs coins is 42 and 5rs coins are 35 then total sum is 2×42 + 5 × 35 is much greater than 77 as said in question. so no way this is right numbers. there are values they contribute by their coins .
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lets assume that 2 rupee coins are x
5 rupee coins are y
so by first condition
2rs coins = 5 time 9f 5rs coins
(1) x = 3y
from 2nd condition
total money accumulated by 2rs coins = 2x
total money accumaulated by 5 rs coins = 5y
so
(2) 2x+ 5y = 77
putting value of x in 2nd equation
2(3y) + 5y = 77
6y + 5y = 77
11y =77
y = 77/11 = 7
so putting value of y in 1st equation
x =3y
x = 3*7= 21
so 2rs coins are 21 and 5rs coins are 7
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