Math, asked by rakeshmenariya007, 9 months ago

plzz solve it fast for me ​

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Answered by amritraj13
2

Answer:

Let triangle ABC

AB= 3x   ; BC= 5x   ; AC= 7x

  Perimeter= 300m

AB+BC+AC= 300

3x+5x+7x= 300

15x= 300

x= 300/15= 20

∵AB= 3x= 3(20)= 60m

  BC= 5x= 5(20)= 100m

  AC= 7x= 7(20)= 140m

             S= a+b+c/2= 300/2= 150

 Area= √s(s-a)(s-b)(s-c)

            √150(150-60)(150-100)(150-140)

            √150*90*50*10

            √2*3*5*5*2*3*3*5*2*5*5*2*5

            2*2*3*5*5*5*√3

            1500√3 m² 

Read more on Brainly.in - https://brainly.in/question/414965#readmore

Answered by TheMoonlìghtPhoenix
5

Step-by-step explanation:

Let the ratios be considered as X.

So our sides will be 3x, 5x and 7x.

Now we are given the perimeter as 300.

3x+7x+5x= 300

15x=300

x= 300/15= 20

So x= 20

Now 3x= 60

5x= 100

7x= 140

So now Using Heron's Formula we get S= 300/2= 150

s-a= 150-60= 90

s-b= 150-100= 50

s-c= 150-140= 10

So ,

 \sqrt{150 \times 10 \times 90 \times 50}

= 2,598.076m² (approx.) is the Area

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