plzz solve it for me .....
Attachments:
Answers
Answered by
1
option A
EXPLANATION:-
let volume of a sphere be V and p be it's density ,then we can write buoyant force at 0 degree Celsius .
F 0°C=Vp0°g. ( p0°=density at 0°C)
Buoyancy at 4°C
= F 4°C=Vp4°g
= F 4°C÷F 0°C = p 4°C÷p 0°C > 1
= F 4°C > F 0°C
Hence, buoyancy will be less in water at 0°C than that in water at 4°C
EXPLANATION:-
let volume of a sphere be V and p be it's density ,then we can write buoyant force at 0 degree Celsius .
F 0°C=Vp0°g. ( p0°=density at 0°C)
Buoyancy at 4°C
= F 4°C=Vp4°g
= F 4°C÷F 0°C = p 4°C÷p 0°C > 1
= F 4°C > F 0°C
Hence, buoyancy will be less in water at 0°C than that in water at 4°C
Similar questions