Question

plzz solve it It is trigonometric identities

Answer 1

Hi ,

LHS = ( cotA )/ [ 2 - sec² A ]

= [ 1/tanA - 1 ] / [ 2 - ( 1 + tan² A ) ]

= ( 1 - tanA ) / [ tan A ( 2 - 1 - tan² A ) ]

= ( 1 - tanA )/ [ tanA ( 1 - tan² A ) ]

= [ cotA ( 1 - tan A ) ] / ( 1 - tan² A )

= [ cotA ( 1 - tan A ) ] / [ ( 1 + tan A ) ( 1 - tanA ) ]

after cancellation ,

= cotA / ( 1 + tanA )

= RHS

I hope this helps you.

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