Math, asked by hnsmaryan, 11 months ago

Plzz solve it it's urgent

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Answered by guptaramanand68
0
See the two attachments, you will get your answer.
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hnsmaryan: how angle fcb=90-x
hnsmaryan: can u plz explain
hnsmaryan: angle fcb should be equal to 90-angle bce
guptaramanand68: In a square, each angle at vertex equals 90°. So(see in figure) Angle DCF+ AngleFCB=90°, x+angleFCB=90°, therefore AngleFCB=90°-x and since FCB+BCE=90°, BCE=x
hnsmaryan: thanks bro ur genius
guptaramanand68: Hey, I am not a genius.
guptaramanand68: Thanks for the compliment.
hnsmaryan: welcome
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