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this is the answer I hope it helps you thank you
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hi friend,
√3x²-8x+4√3=0
√3x²-6x-2x+4√3=0
√3x(x-2√3)-2(x-2√3)=0
(√3x-2)(x-2√3)=0
x=2/√3,2√3
we know sum of roots ,= - x coefficient /x² coefficient
2/√3+2√3=8/√3
8/√3=8/√3
hence verified
we know that product of roots is constant term /x² coefficient
(2/√3)(2√3)=4√3/√3
4=4
hence verified
Plz mark brainliest plzzzzxx.
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