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Given f(x) = ax^3 - x^2 + x + 4.
Given x = -1/3 is a zero of the polynomial.
Plug x = -1/3 in f(x), we get
a(-1/3)^3 - (1/3)^2 + (-1/3) + 4 = 0
-a/27 - 1/9 - 1/3 + 4 = 0
-a/27 = -32/9
-a = -96
a = 96.
Therefore the value of a = 96.
Hope this helps!
Given x = -1/3 is a zero of the polynomial.
Plug x = -1/3 in f(x), we get
a(-1/3)^3 - (1/3)^2 + (-1/3) + 4 = 0
-a/27 - 1/9 - 1/3 + 4 = 0
-a/27 = -32/9
-a = -96
a = 96.
Therefore the value of a = 96.
Hope this helps!
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