Question

Plzz solve it stepwise

Answer 1

$Given : 4sin^{-1} x + cos^{-1}x = \pi$

$= \ \textgreater \ 4 sin^{-1} x = \pi - cos^{-1} x$

$= \ \textgreater \ 4sin^{-1} x = \pi - ( \frac{ \pi }{2} - sin^{-1} x)$

$= \ \textgreater \ 4 sin^{-1} = \frac{ \pi }{2} + sin^{-1} x$

$= \ \textgreater \ 4 sin^{-1} x - sin^{-1} x = \frac{ \pi }{2}$

$= \ \textgreater \ 3 sin^{-1} x = \frac{ \pi }{2}$

$= \ \textgreater \ sin^{-1} x = \frac{ \pi }{6}$

$= \ \textgreater \ x = sin \frac{ \pi }{6}$

= > x = 1/2


Hope this helps!

Answer 2

Hi,

Please see the attached file!



Thanks