plzz solve it urgent plzz
ques 20
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SUMANSINGHRAJPUT:
leap year
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We know that Number of days in January = 31(Leap year and non-leap year).
= > 4 weeks + 3 days.
Now,
For those 3-days, there are 7-possibilities, they are:
(a) Mon, Tues, Wed
(b) Tues, Wed, Thur
(c) Wed, Thurs, Fri
(d) Thurs, Fri, Sat
(e) Fri, Sat, Sun
(f) Sat, Sun, Mon
(f) Sun, Mon, Tue
The total number of possible outcomes = 7.
The number of outcomes having Mondays = 3.
Therefore Required Probability = 3/7.
Hope this helps!
= > 4 weeks + 3 days.
Now,
For those 3-days, there are 7-possibilities, they are:
(a) Mon, Tues, Wed
(b) Tues, Wed, Thur
(c) Wed, Thurs, Fri
(d) Thurs, Fri, Sat
(e) Fri, Sat, Sun
(f) Sat, Sun, Mon
(f) Sun, Mon, Tue
The total number of possible outcomes = 7.
The number of outcomes having Mondays = 3.
Therefore Required Probability = 3/7.
Hope this helps!
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