Math, asked by granthjain11, 7 months ago

plzz solve its too urgent ​

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Answered by cherry764296
0

Answer:

lHio friend

Here is ur answer:

(i) 4x2 +9y2 + 16z2 + 12xy - 24yz - 16xz Using identity, (a + b + c)2 = a2 + b2 + c2 + 2ab +

2bc + 2ca 4x2 +9y2 + 16z2 + 12xy - 24yz - 16xz

= (2x)2 + (3y)2 + (-4z)2 + (2x2xx3y) + (2x3yx-4z) + (2x-4zx2x)

= (2x + 3y - 4z)2 =

=

(2x + 3y - 4z) (2x + 3y - 4z)

(ii) 2x2 + y2 + 8z2 - 2v2 xy + 4v2 yz 8xz Using identity, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

2x2 + y2 + 8z2 - 2v2 xy + 42 yz - 8xz = (-V2x)2 + (y)2 + (2/2z)2 + (2x-v2xxy) + (2xyx2v2z) + (2×2v2zx-v2x) = (-v2x + y +2V2z)2

(-V2x + y + 2v2z) (-/2x + y + 2v2z)

HOPE IT HELPS YOU.. PLEASE MARK ME AS BRAINLIEST...

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