Question

plzz solve my question its emergency

Answer 1

Hey friend
here is your answer

i.
$12 {x}^{2} - 7x + 1 \\ 12 {x}^{2} - 4x - 3x + 1 \\ 4x(3x - 1) - 1(3x - 1) \\ (3x - 1)(4x - 1)$

ii.
$6 {x}^{2} + 5x - 6 \\ 6 {x}^{2} + 9x - 4x - 6 \\ 3x(2x+ 3) - 2(2x + 3) \\ (2x + 3)(3x - 2)$

glad to help you
hope it helps
thank you.

Answer 2

12x^2-7x+1
=12x^2-3x-4x+1
=3x(4x-1)-1(4x-1)
=(4x-1)(3x-1)


6x^2+5x-6
=6x^2+9x-4x-6
=3x(2x+3)-2(2x+3)
=(2x+3)(3x-2)

Hope it helps.