Question

plzz solve plz plz plz​

Answer 1

distance =(x2-x1). (y2- y1)

20=(x-1)(20-4)

20=(x-1)(16)

20=16x-16

36=16x

36/16=x

9/4

Answer 2

Q) Find the values of x so that the distance between the points A(1,4) and B(x,20) is 20.

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Answer :-

x = 13 or x = -11

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Given :-

Two points

• A (1, 4)
• B (x,20)

To Find :-

Value of x

Solution :-

To find distance between 2 points we use the following distance formula :-

$d =\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1})^2}$

Substituting the values :-

$d=\sqrt{(x-1 )^{2} +(20-4)^2}=20$

squaring on both sides :-

$=>(x-1)^2+256=400$

$=>(x-1)^2=400-256=144$

taking square root on both sides :-

$\sqrt{(x-1)^2} = \sqrt{144} \\x-1=12\\x=1+12\\x=13$

or

$\sqrt{(x-1)^2} = \sqrt{144} \\x-1=-12\\x=1-12\\x=-11$

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Therefore x = 13 or x = -11