plzz solve Q 2and Q5..
Attachments:
Soumika1:
its urgent
Answers
Answered by
1
2) the no. of zeroes of polynomial is equal to the no. of x-intercepts ....
=> No. of zeroes of polynomial P(x) is equal to 1 .
5) Using Pythagoras theorem in triangle OPQ ( right angled at P) ,
=> OQ^2 = OP^2 + PQ^2
=> PQ^2 = OQ^2 - OP^2
=> PQ^2 = (12)^2 - (5)^2 = 144 - 25
=> PQ = √119 .
=> No. of zeroes of polynomial P(x) is equal to 1 .
5) Using Pythagoras theorem in triangle OPQ ( right angled at P) ,
=> OQ^2 = OP^2 + PQ^2
=> PQ^2 = OQ^2 - OP^2
=> PQ^2 = (12)^2 - (5)^2 = 144 - 25
=> PQ = √119 .
5 is wrong
2 is correct
wait a min. , let me check it again
answer is root of 119
yeah! got it .. thanks for telling me
i got my mistake and corrected it ....
Similar questions