plzz solve Q 8 in the following image
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For vessel,
Heat energy needed = mcΔt
= 50x400x(30-5)
= 50x400x25
= 500000J (i)
For water,
Energy needed = 250x4200x(30-5)
=250x4200x25
=26250000 (ii)
For ice,
Let the mass be m
Energy needed to melt = m x 336000
= 336000m (iii)
Energy needed after melting = m x 4200x(5-0)
= m x 4200x5
= 21000m (iv)
From (i), (ii), (iii) and (iv)
500000+26250000 = 336000m+21000m
26750000 = 357000m
m = 26750000/357000
m = 74.929
m = 74.93g
∴ Mass of ice needed = 74.93g
Heat energy needed = mcΔt
= 50x400x(30-5)
= 50x400x25
= 500000J (i)
For water,
Energy needed = 250x4200x(30-5)
=250x4200x25
=26250000 (ii)
For ice,
Let the mass be m
Energy needed to melt = m x 336000
= 336000m (iii)
Energy needed after melting = m x 4200x(5-0)
= m x 4200x5
= 21000m (iv)
From (i), (ii), (iii) and (iv)
500000+26250000 = 336000m+21000m
26750000 = 357000m
m = 26750000/357000
m = 74.929
m = 74.93g
∴ Mass of ice needed = 74.93g
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