plzz solve question 1 to3
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1) we will write it as 0.32 (bar on 32)
Let x = 0.32 bar.... (1)
Then 10x = 32.32 bar....(2)
Subtract (1) from(2)
10x-x= 32.32bar-. 32 bar
And solve you will get the value of x
Let x = 0.32 bar.... (1)
Then 10x = 32.32 bar....(2)
Subtract (1) from(2)
10x-x= 32.32bar-. 32 bar
And solve you will get the value of x
sharan121:
for the second q. both will be terminating
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and 3 with the formula (a+b) (a-b)
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