Question

plzz solve question 10 .......

Answer 1

Heya..

Given :

AD = BE .. Eq 1.

Angle A = Angle B

=) AC = CB .. Eq 2.

(Sides opposite to equal angles are equal)

Subtract eq 1 by eq 2.

=) AC - AD = CB - BE

=) CD = CE

Hence D is a mid point of AC and E is a mid point of BC.

By Mid point theorem,

DE ll AB.

Hope it's helpful to u.

Answer 2

Hey friend ☺


it's too easy .
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given --∆ABC in which <A=<B and DE//AB, in which DE intersect ACand BE at D And E respectively

<A=<B

so ,As we know that the angles are equal then its corresponding sides are also equals
so,

CB=AC. ------1)

To proove --AD=BE

proof We have

CD/AD =CE/BE 【•°•DE//AB so by using Thales theorm 】

if we adding 1 on both side

then ,

CD/AD+1=CE/BE+1

CD+AD/AD =CE+BE/BE

AC/AD=BC/BC

AC/AD=AC/BE -----[from equation (1)]

so AC and AC are cancelled

now ,

1/AD=1/BE

AD=BE (prooved here )

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Hope it helps you !

!@Rajukumar111