Question

plzz Solve question no 11 ND 12​

Answer 1

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Refer the attachment for Question no 11.✌️⬆️

$\huge\boxed{\fcolorbox{red}{white}{Answer 12}}$

$\huge\pink{\mid{\underline{\overline{\tt Solution:-}}\mid}}$

For finding area of the park, we have

$2s = 50m + 80m + 120m = 250m. \\ s = 125m$

Let,

$a = 120m \\ b = 80m \\ c = 50m$

by using Heron's formula

Therefore, area of the park=

$= > \sqrt{s(s - a)(s - b)( s-c )}$

$= > \sqrt{125(125 - 120)(125 - 80)(125 - 50)} \\ = > \sqrt{125 \times 5 \times 45 \times 75 {m}^{2} } \\ = 375 \sqrt{15} {m}^{2}$

Also, perimeter of the park= AB+BC+CA=250m

Therefore, length of the wire needed for fencing=250m - 3m(to be left for gate)

=247 m

And so the cost of fencing= Rs 20×247=Rs 4940.

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Answer 2

Answer:

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