Math, asked by jiya8980, 1 year ago

plzz solve question no. 3

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Answered by BEJOICE

Given equations are
$x + y = 7xy \\ 2x - 3y = - xy \\ dividing \: \: both \: \: the \: \: equations \: \: by \\ xy \\ \frac{1}{y} + \frac{1}{x} = 7 \\ \frac{2}{y} - \frac{3}{x} = - 1$
$let \: \: u = \frac{1}{x} \: \: and \: \: v = \frac{1}{y } \\ then \: \: the \: \: equations \: becomes \\ v + u = 7 - - - (1)\\ 2v - 3u = - 1 - - - (2)$
$2 \times (1) - (2) \: \: gives \\ 5u = 15 \\ u = 3 \\ substituting \: \: in \: \: (1) \\ v = 7 - 3 = 4$
$therefore \\ x = \frac{1}{3} \\ y = \frac{1}{4}$

jiya8980: even i am getting the same answer

jiya8980: but in the book its given 0

jiya8980: for both x nd y

BEJOICE: definitely, x and y equal to 0 is also an answer

BEJOICE: but it is the trivial solution

BEJOICE: substituting the values of x and y we got in the given equations, satisfies the equation

BEJOICE: So this is the non-trivial solution

BEJOICE: thanks worry. Go ahead with this solution

jiya8980: okay thank you

BEJOICE: welcome

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