Question

plzz solve question no.- 9,10​

Answer 1

here's your solution

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Answer 2

Answer:

9) 4/cot²30˚ + 1/sin²30˚ - 2cos²45˚ -sin²0˚

  =4/(√3)² + 1/(1/2)² - 2(1/√2)² - 0²

  =4/3 + 1/4 - 1-0

  = 7/12

10) 1/cos²30˚ + 1/sin³30˚ - tan²45˚/2 - 8sin²90˚

  = 1/(√3/2)² + 1/(1/2)³ - (1)²/2 - 8(1)

  = 4/3 + 8 - 1/2 -8

  = 5/6