Question

plzz solve question no.(vii)

Answer 1

4x²-4a²x+(a⁴-b⁴)=0

4x²-2(a²-b²)x-2(a²+b²)x+(a²-b²)(a²+b²)=0

2x{2x-(a²-b²)}-(a²+b²){2x-(a²-b²)}=0

{2x-(a²-b²)}{2x-(a²+b²)}=0

2x=a²-b²

x=(a²-b²)/2

2x=a²+b²

x=(a²+b²)/2

i hope its help u.....✌✌✌✌✌