Question

Plzz solve the above sum
(Only the Question of No. 5 )

Answer 1

circumference of the base of the cylinder = 2πr = 110cm
2πr=110
πr=55
r=55/π cm

CSA of cylinder =2πrh=4400cm²
πrh=2200
hπ*55/π=2200
55h=2200
h=2200/55
h=440/11
h=40cm

volume of cylinder=πr²h=π*55/π*55/π*40
=55*55/π*40
=38500cm³


HOPE IT HELPS

Answer 2

We know that curved surface area of the cylinder = 2πrh.

We know that volume of cylinder = πr^2h

According to Question,

(i)

Given that curved surface area of cylinder = 4400 cm^2.

⇒ 2πrh = 4400

⇒ πrh = 2200

⇒ πr = (2200/h).    ----- (1)

(ii)

Given circumference of base of a cylinder = 110 cm.

⇒ 2πr = 110

⇒ 2 * (2200/h) = 110

⇒ 4400/h = 110

⇒ 4400 = 110h

⇒ h = 40.

Substitute h = 40 in (1), we get

⇒ πr = (2200/40)

⇒ πr = 55

⇒ (22/7) * r = 55

⇒ 22r = 385

⇒ r = 17.5

(iii)

Volume of cylinder = πr^2h

                                = (22/7) * (17.5)^2 * (40)

                                = (22/7) * (306.25) * 40)

                                = 22 * 43.75 * 40

                                = 38500 cm^2.

Therefore:

⇒ Height of the cylinder = 40 cm.

⇒ Volume of the cylinder = 38500 cm^2.

Hope it helps!