Math, asked by AdityaKumar91133, 1 year ago

plzz solve the question fast as u can
Q no.18

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Answers

Answered by nikiravi
1

Let the CP of saree and that of sweater be x and y respectively.


Case 1.


Given that saree is sold at 8% profit


=> SP of saree = x + 8x/100 = 108x/100


Also, sweater is sold at 10% discount


=> SP of sweater = y - 10y/100 = 9y/10


Given that saree and sweater fetch Rs 1008,


108x/100 + 9y/10 = 1008


=> 108x+90y/100 = 1008


=> 108x + 90y = 100800 => 6x + 5y = 5600 => x = 5600-5y/6 (i)  


Case 2.


Given that saree is sold at 10% profit


SP of saree = x + 10x/00 = 11x/10


Also, sweater is sold at 8% discount


=> SP of sweater = y - 8y/100 = 92y/100 =


Given that saree and sweater fetch Rs 1028,


11x/10 + 92y/100 = 1028


=> 110x+92y/100 = 1028


=> 110x+92y = 102800


Putting value of (i)


110 (5600-5y/6) + 92y = 102800


=> 616000-550y/6 + 92y = 102800


=> 616000-550y-552y/6 = 102800


=> 616000+2y/6 = 102800


=> 616000+2y = 616800


=> 2y = 800


=> y = Rs400


From (i),


x = 5600 - 5*400/6


x = 5600-1200/6


x = 4200/6


=> x = Rs700


Therefore, SP of saree = Rs700


List price of sweater = Rs 400


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