Question

plzz solve the value of k​

Answer 1

Answer:

4

Step-by-step explanation:

b²-4ac=0

∴(2(k+2))²=4×k×(k+5)

→4k²+16k+16 = 4k²+20k

→4k=16

→k=4

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Answer 2

Answer:

K = 4

Step-by-step explanation:

As we know that for real and equal roots

$d = {b}^{2} - 4ac \: = \: 0 \\ {2k + 4}^2 - {4k}^{2} - 20k = 0 \\ {4k}^{2} + 16 + 16k - {4k}^{2} - 20k = 0 \\ 16 - 4k = 0 \\ 4k = 16 \\ k = 4$

so ,answer is 4.....