Question

plzz solve these plzz

Answer 1

heya...!!!

let A = X


$\frac{sinx + sin5x + sin9x}{cosx + cos5x + cos9x} \\ \\ = > \frac{(sinx + sin9x) + sin5x}{(cosx + cos9x) + cos5x} \\ \\ = > \frac{2 {sin (\frac{x +9x}{2} )cos (\frac{9x - x)}{2} } + sin5x}{2cos (\frac{x + 9x}{2} )cos( \frac{9x - x}{2} ) + cos5x} \\ \\ = > \frac{2sin5cos4x + sin5x}{2cos5xcos4x + cos5x} \\ \\ = > \frac{sin5x(2cos4x + 1)}{cos5x(2cos4x + 1} \\ \\ = > \frac{sin5x}{cos5x} = tan5x$