plzz solve thi question
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(x/x+1/x)(x^2/x^2+1/x^2)(x/x-1/x)(x^4/x^4+1/x^4)
= (1+1/x)(1+1/x^2)(1-1/x)(1+1/x^4)
= 1(1+1/x^2)+1/x(1+1/x^2)1(1+1/x^4)-1/x(1+1/x^4)
= 1+1/x^2+1/x+1/x^3*1+1/x^4-1/x+1/x^5
= 1+x+x^2+1*1+x-x^4+1
= 2+x+x^2*2+x-x^4
= 4+2x+2x-2x^4+x^2+2x^2-x^5+x^3-x^6
= 4+4x-2x^4+3x^2-x^5+x^3-x^6
Hope, it helps
= (1+1/x)(1+1/x^2)(1-1/x)(1+1/x^4)
= 1(1+1/x^2)+1/x(1+1/x^2)1(1+1/x^4)-1/x(1+1/x^4)
= 1+1/x^2+1/x+1/x^3*1+1/x^4-1/x+1/x^5
= 1+x+x^2+1*1+x-x^4+1
= 2+x+x^2*2+x-x^4
= 4+2x+2x-2x^4+x^2+2x^2-x^5+x^3-x^6
= 4+4x-2x^4+3x^2-x^5+x^3-x^6
Hope, it helps
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