Question

plzz solve this 4 sum polynomial

Answer 1

p(x) = x^4–2x^3+3x^2-ax+b-5 = 0

p(1) = 1–2+3-a+b-5 = 0, or -a+b-3=0, or -a+b = 3 …(1)

p(x) = x^4–2x^3+3x^2-ax+b-19 = 0

p(-1) = 1+2+3+a+b-19=0, or a+b-13=0, or a+b = 13 …(2)

Add (1) and (2), to get

2b=16, or b = 8. From (2), a = 13–8=5

Answer 2

⭐⭐Hello friend....Ur answer is here⤵⤵

⚫Q.11 p (x)=2x^3+3x^2-11x-3 , g (x)=x+1/2

➡ put x= -1/2

➡ 2 (-1/2)^3+3 (-1/2)^2-11 (-1/2)-3

➡ -1/4+3/4+11/2-3

➡-1+3+22-12/4

➡ 3

⚫Q.12 p (x)=x^3-ax^2+6x-a , g (x)=x-a

➡put x=a

➡(a)^3-a (a)^2+6 (a)-a

➡a^3-a^3+5a

➡5a

⚫Q.13 when 2x^3+x^2-ax+2 is divided by (x-2) then the remainder is..

➡ 2 (2)^3+(2)^2-2a+2

➡ 16+4-2a+2

➡ 22-2a

Similarly when 2x^3-3x^2-3x+a is divided by (x-2) then the remainder is..

➡ 2 (2)^3-3 (2)^2-3 (2)+a

➡16-12-6+a

➡a-2

According to question..

➡ 22-a=a-2

➡2a=24

➡a=12

I HOPE IT IS HELPFUL TO YOU ☺