Plzz solve this....... (^_^)
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Step-by-step explanation:
First interest
P = ₹ 500
r = 6 %
Let time be t
I = P r t / 100
= > I = ( 500 × 6 × t ) / 100
= > I = 5 × 6 × t
= > I = 30 t .......................( 1 )
Second interest
P = ₹ 900
r = 4 %
Time = t - 2 since it is 2 years after the first interest .
Hence the time will always be less than the first interest .
I = P r t / 100
= > I = 900 × 4 × ( t - 2 ) / 100
= > I = 3600 ( t - 2 ) / 100
= > I = 36 ( t - 2 ) ..................( 2 )
From ( 1 ) and ( 2 )
36 ( t - 2 ) = 30 t
⇒ 36 t - 72 = 30 t
⇒ 36 t - 30 t = 72
⇒ 6 t = 72
⇒ t = 72/6
⇒ t = 12
Total interest :
I₁ + I₂ = 36 ( t - 2 ) + 30 t
= 36 ( 12 - 2 ) + 30 × 12
= 36 × 10 + 360
= 360 + 360
= 720
edit korchi....besi dhokas na ....tarpor laste atkei jabe xd
suppose 2014 loan was taken , after 2 years another loan will be taken 2016 will be the year ....suppose interest is paid on 2020 ..so t1 = 2020 - 2014 = 6 ....t2 = 2020 - 2016 = 4.....always the first interest will be more because it is earlier than the latter !
if interest is paid on 2016 itself , then t2 = 0 and t1 = 2 ...always t1>t2 u can take any year...
Answered by
24
First interest
P = ₹ 500
r = 6 %
Let time be t
I = P r t / 100
= > I = ( 500 × 6 × t ) / 100
= > I = 5 × 6 × t
= > I = 30 t .......................( 1 )
Second interest
P = ₹ 900
r = 4 %
Time = t - 2 since it is 2 years after the first interest .
Hence the time will always be less than the first interest .
I = P r t / 100
= > I = 900 × 4 × ( t - 2 ) / 100
= > I = 3600 ( t - 2 ) / 100
= > I = 36 ( t - 2 ) ..................( 2 )
From ( 1 ) and ( 2 )
36 ( t - 2 ) = 30 t
⇒ 36 t - 72 = 30 t
⇒ 36 t - 30 t = 72
⇒ 6 t = 72
⇒ t = 72/6
⇒ t = 12
Total interest :
I₁ + I₂ = 36 ( t - 2 ) + 30 t
= 36 ( 12 - 2 ) + 30 × 12
= 36 × 10 + 360
= 360 + 360
= 720
P = ₹ 500
r = 6 %
Let time be t
I = P r t / 100
= > I = ( 500 × 6 × t ) / 100
= > I = 5 × 6 × t
= > I = 30 t .......................( 1 )
Second interest
P = ₹ 900
r = 4 %
Time = t - 2 since it is 2 years after the first interest .
Hence the time will always be less than the first interest .
I = P r t / 100
= > I = 900 × 4 × ( t - 2 ) / 100
= > I = 3600 ( t - 2 ) / 100
= > I = 36 ( t - 2 ) ..................( 2 )
From ( 1 ) and ( 2 )
36 ( t - 2 ) = 30 t
⇒ 36 t - 72 = 30 t
⇒ 36 t - 30 t = 72
⇒ 6 t = 72
⇒ t = 72/6
⇒ t = 12
Total interest :
I₁ + I₂ = 36 ( t - 2 ) + 30 t
= 36 ( 12 - 2 ) + 30 × 12
= 36 × 10 + 360
= 360 + 360
= 720
You have coped from the 1st user !!
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